(16/2^2)+8*2^3-(1/2)(3^2*4-25)^2

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Solution for (16/2^2)+8*2^3-(1/2)(3^2*4-25)^2 equation:


16/(2^2)+8*2^3-((1/2)*(4*3^2-25)^2) = 0

16/4+8*2^3-((1/2)*(4*3^2-25)^2) = 0

8*2^3-((1/2)*(4*3^2-25)^2)+4 = 0

8*8-((1/2)*(4*3^2-25)^2)+4 = 0

4-((1/2)*(4*3^2-25)^2)+64 = 0

68-((1/2)*(4*3^2-25)^2) = 0

68-(1/2*(4*3^2-25)^2) = 0

68-(1/2*(4*9-25)^2) = 0

68-(1/2*(36-25)^2) = 0

68-(1/2*11^2) = 0

68-(1/2*121) = 0

68-121/2 = 0

15/2 = 0

L <> R

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